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💚 — Compare Trio: Max of 3

Task​

  • Create a file named max3.py.
  • Read three integers a, b, c.
  • Print the largest value.
  • Test with a tie case (like 5, 5, 1).
  • (Optional) Print the smallest value too.
  • (Optional) Print BOTH using built-ins: max(...) and min(...).

Example run​

$ python max3.py
a: 5
b: 5
c: 1
largest = 5
smallest = 1

Solution (ATTEMPT FIRST)​

Show spoiler code (max3.py)

Two ways are shown: built-ins (easy) and manual comparisons (commented).

max3.py
"""max3.py

Find the largest of three numbers (and optionally the smallest).
"""

a = int(input("a: ").strip())
b = int(input("b: ").strip())
c = int(input("c: ").strip())

# Easiest: use built-in max/min
largest = max(a, b, c)
smallest = min(a, b, c)

print(f"largest = {largest}")
print(f"smallest = {smallest}")

# --- Alt approach (commented): manual comparisons ---
# largest = a
# if b > largest: largest = b
# if c > largest: largest = c
# print(largest)

Docs / Tutorials​